The percentage of three elements calcium , carbon and oxygen in a simple of calcium carbonate is given as; calcium=40.%; carbon=12%;oxygen=48%. If the law of constant proprotion is true,what weight of these element will be present in 1.5g of another sample of calcium carbonate.
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Answers
Answered by
79
40percent of calcium ,
40/100×1.5=0.6gm
12percent of carbon ,
12/100×1.5=.18gm
48percent of oxygen
48/100×1.5=.72gm.....
40/100×1.5=0.6gm
12percent of carbon ,
12/100×1.5=.18gm
48percent of oxygen
48/100×1.5=.72gm.....
ali4726:
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Answered by
21
Answe0. 6 ca, 0.18C,0.72O
Explanation:
Find the percentage of each element by x/100*1.5
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