Question

the perimeter if a rhombus is 40 cm and the length of one diagonal is 16 cm find the length of the other diagonal.


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Answer 1

Answer:

Step-by-step explanation:First of all we will find length of side of rhombus by using formula

the perimeter of rhombus = 4 * sides

40 = 4 * sides

10 cm = side of rhombus

now we know that diagonal of rhombus are perpendicular bisectors of each other hence by using Pythagoras theorem

(10)squared = (8)squared + (x)squared

6 cm = x

12 cm is length of other diagonal .....(6 * 2)=12 cm

Now area of rhombus = 1/2 * product of length of diagonals

= 1/2 * 16 *12

=96 sq.cm

length of other diagonal is 12 cm and area of rhombus is 96 sq.cm

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Answer 2

Step-by-step explanation:

let the length of each side of rhombus be a. perimeter of rhombus= 40 cm.

a+a+a+a=40

4a=40

a=10cm

it's one diagonal is 16 cm.

since ,diagonal of rhombus intersect each

other at right angles.

length of other diagonal will be: length of other diagonal= 2(102-82)=2*6=12

cm.

and we also know that:

area of rhombus=D1/2xd1xd2. =1/2x12x16=12*8=96cm2. answer