The perimeter of a bigger square is 12 m more than the perimeter of a smaller square than the perimeter of a smaller square . three times the area of the
smaller square is 11m square more than the area of the bigger square . find the length of bigger square
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let the length of side of smaller square be 'y' and the bigger be 'x'.
4x=12+4y,
x=3+y,
area of bigger square =x^2,
area of smaller square=y^2,
3y^2=11+x^2,
by substituting,
3y^2=11+(3+y)^2,
y^2 -3y-10=0,
"y=5" that is, length of the smaller one is5,
x=5+3=8.
therefore the length of the bigger square is 8.
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