the perimeter of a equilateral triangle is equal to the perimeterof a rhombus if the perimeter of the equilateral triangle is 52 and one diagonal of the rhombus is24 find the other diagonal
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hii this is the answer
first diagonal of rhombus= 24
let,
the second diagonal of rhombus= a
perimeter= l×b
24×a = 52
a = 52/24
a = 13/6
checking
24 × 13/6 = 52
4 × 13 = 52
LHS = RHS
hence verified
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