the perimeter of a parallelogram is 140 CM if one of the side is longer than the other by 10 cm find the length of each of its sides
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Let one side be l cm Then, other side is (l+10) cm
perimeter of a parallelogram = 2(l+b) = 2(l+l+10) = 4l + 20
but perimeter is 140 CM as per the question
so, 4l + 20 = 140 or l = 120÷4 = 30
the sides are 30 cm and 40(30+10) cm respectively .
perimeter of a parallelogram = 2(l+b) = 2(l+l+10) = 4l + 20
but perimeter is 140 CM as per the question
so, 4l + 20 = 140 or l = 120÷4 = 30
the sides are 30 cm and 40(30+10) cm respectively .
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