Question

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width?

Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is \(P=2l+2w.\)
What is the smallest possible measurement of the width? Justify your answer by showing all your work.

Answer 1

Answer:

Perimeter of the parallelogram ≥ 40feet

Perimeter of the parallelogram = 2(l+b) = 2(6+b) = 12+2b

12+2b ≥ 40

2b ≥ 28

b ≥ 14

⇒the smallest possible measurement of width = 14feet