Question

The perimeter of a protractor is a 77cm. Find the area enclosed by the protractor.

Answer 1

Answer:

Perimeter of protractor =77

$1 \div 2 \times 2\pi \: r = 77$22/7×r=77

r=77×7/22

r=49/2

Area =

$1 \div 2 \times \pi \: r ^{2}$

1/2×22/7×49/2×49/2

11/7×49/2×49/2

943.25

Step-by-step explanation:

Hope this help u

Answer 2

Our required area is 471.625 sq. cm.

Step-by-step explanation:

Since we have given that

Perimeter of circle = 77 cm

As we know the formula, we get that

$2\tpi r= 77\\\\2\times \dfrac{22}{7}\times r=77\\\\r=\dfrac{7\times 77}{2\times 22}\\\\r=12.25\ cm$

So, Area enclosed by a protractor is given by

$\pi r^2\\\\=\dfrac{22}{7}\times 12.25\times 12.25\\\\=471.625\ cm^2$

Hence, our required area is 471.625 sq. cm.

# learn more:

If the perimeter of a protractor is 90cm. find the radius of the protractor.

https://brainly.in/question/2690700