Question

the perimeter of a rectangle and square and equal if length of the rectangle Is 8 cm and breadth is 6 m find the are of the square​

Answer 1

Given:

• The perimeter of a rectangle and square are equal.

• Length of the rectangle is 8 cm

• Breadth of the rectangle is 6 m

To find :

• The are of the square =?

Step-by-step explanation:

We know that,

Perimeter of a rectangle = 2( l + b )

Substituting the values in the above formula, we get,

= 2 × ( 8 + 6 )

= 2 × 14

= 28 cm

In the above question it is given that, Perimeter of rectangle = perimeter of square.

So,

Perimeter of rectangle = Perimeter of square.

We know that,

Perimeter of square = 4 × side

And, Perimeter of rectangle = 28 cm

Substituting the values in the above formula, we get,

28 = 4 × side

28 = 4 side

Or 4side = 28

Side = 28/4

Side = 7

Therefore, The side of the square = 7 cm

Now,

We have to find the Area of the square,

We know that,

Area of a square = side²

Substituting the values in the above formula, we get,

= 7²

= 7 × 7

= 49

Thus, Area of a square = 49 cm²

Answer 2

$\mathtt{ \huge{\fbox{Solution :)}}}$

Given ,

• The perimeter of a rectangle and square are equal

• Length (l) and breadth (b) of rectangle are 8 cm and 6 cm

According to the question ,

➡2(l + b) = 4 × side

➡2(8 + 6) = 4 × side

➡2(14) = 4 × side

➡4 × side = 28

➡side = 28/4

➡side = 7 cm

Hence , the side of the square is 7 cm

We know that , the area of square is given by

$\large \mathtt{ \fbox{Area \: of \: square = {(side)}^{2} }}$

Thus ,

➡Area = (7)²

➡Area = 49 cm²

Hence , the area of square is 49 cm²

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