Question

THE PERIMETER OF A RECTANGLE AND SQURE ARE SAME .IF THE LENGTH AND BREADTH OF THE RECTANGLE ARE 25 AND 17 .WHICH FIGURE HAS GRETER AREA AND HOW MUCH

Answer 1

ANSWER:-

It is given that

Perimeter of rectangle=perimeter of square

then,2(l+b)=4×side of square

2(25+17)=4×side

84=4×Side

then,Side of square=84/4=21

Now,Area of square=side×side

=21×21=441

Area is rectangle=l×b=425

From this,we know that

area of square is greater than rectangle by

441-425=16 units

HOPE IT HELPS YOU

Answer 2

Answer :

SQUARE figure ks greater by 16 units.

Explaination :

Given :

Length of RECTANGLE = 25
Breadth of the RECTANGLE = 17

→ PERIMETER of RECTANGLE = Perimeter of the SQUARE ( according to the question )

→ Perimeter of RECTANGLE = 2(l + b )

=> 2 (25 + 17 )

=> 50 + 34

=> $\large{\green{\boxed{\green{\boxed{\red{\textsf{84 units}}}}}}}$

$\therefore$ The PERIMETER of SQUARE is 84 units.

→ Side of the SQUARE =

=> 84/4

=> $\large{\green{\boxed{\green{\boxed{\red{\textsf{21 units}}}}}}}$

=> $\therefore$ The Side of the SQUARE is 21 units.

→ AREA of the SQUARE = Side × Side

=> 21 × 21

=>$\large{\green{\boxed{\green{\boxed{\red{\textsf{441 sq. units }}}}}}}$

→ AREA of the RECTANGLE = L × B

=> 25 × 17

=> 425 sq.units.

★ 441 > 425 ★

$\therefore$ Area of SQUARE > Area of RECTANGLE

=> 441 - 425

=> $\large{\green{\boxed{\green{\boxed{\red{\textsf{16 sq.units}}}}}}}$

$\therefore$ Area of the SQUARE is greater than the area of the RECTANGLE by 16 units.