Question

the perimeter of a rectangle is 12 m if its length is 5 m more than its breadth, find the sides of the rectangle​

Answer 1

Answer:

Let the breadth be x m

Length = x + 5 m

ACQ,

2 ( Length + Breadth ) = Perimeter of rectangle

2 ( x + 5 + x ) = 12

( x + 5 + x ) = 6

2x + 5 = 6

2x = 1

x =

$\frac{1}{2}$

Breadth =

$\frac{1}{2}$

Length =

$\frac{1}{2} + 5 = \frac{1}{2} + \frac{10}{2} = \frac{11}{2} = 5 \frac{1}{2}$

Answer 2

Step-by-step explanation:

perimeter of a rectangle is 12 m

length is 5m more than breadth

then

length = breadth+5

perimeter of a rectangle = 2(length+breadth)

12 =2(breadth+5+breadth)

12 = 2(2breadth+5)

12 = 4breadth+5

12-5 = 4breadth

8 = 4breadth

breadth = 8/4

breadth = 2m

length=breadth+5

length=2+5

length=7m

the sides of rectangle are 7m and 2m

hope it's help you