Question

The perimeter of a rectangle is 120 cm. If its length is 40 cm, what will be the area?​

Answer 1

Answer:

800cm

Step-by-step explanation:

A=wl

P=2(l+w)

Solving forA

A=Pl

2﹣l2=120·40

2﹣402=800cm²

Answer 2

Question:-

The perimeter of a rectangle is 120 cm. If its length is 40 cm, what will be the area?

Answer:-

• The area of rectangle is 800 cm².

To find:-

• Area of rectangle

Solution:-

• Perimeter of rectangle = 120 cm
• Length of Rectangle = 40 cm

Firstly , we have to find the breadth of rectangle,

As we know,

$\large{ \boxed{ \mathfrak{ perimeter = 2(l + b)}}}$

where,

• l = length of Rectangle
• b = breadth of rectangle

Put the values in the formula

• Let the breadth of rectangle be x

According to question,

$\large{ \tt : \implies \: \: \: \: 2(40 + x) = 120}$

$\large{ \tt : \implies \: \: \: \: 40 + x = \frac{120}{2} }$

$\large{ \tt : \implies \: \: \: \: 40 + x = 60}$

$\large{ \tt : \implies \: \: \: \: x = 60 - 40}$

$\large{ \tt : \implies \: \: \: \: x = 20}$

• The breadth of rectangle is 20 cm.

Now, we have to find the area of rectangle.

As we know,

$\large{ \boxed{ \mathfrak{ area = l \times b}}}$

Put the values in the formula.

According to question,

$\large{ \tt : \implies \: \: \: \: area = 40 \times 20}$

$\large{ \tt : \implies \: \: \: \: area = 800}$

Hence,

The area of rectangle is 800 cm².