The perimeter of a rectangle is 130 m.If its breadth is 30 m,find its length and area.
Answers
Answered by
2
we know ,
perimeter =2(l+b)
hence,
2(l+30)=130
2l+60=130
2l=130-60
l=70/2
l=35
perimeter =2(l+b)
hence,
2(l+30)=130
2l+60=130
2l=130-60
l=70/2
l=35
Answered by
2
perimeter of rectangle = 2×{l+ b}
130=2×{l+30}
130÷2 = (l+30)
65 = l+30
65-30=l
length=35
area of rectangle = l×b
35×30=1050
130=2×{l+30}
130÷2 = (l+30)
65 = l+30
65-30=l
length=35
area of rectangle = l×b
35×30=1050
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