Question

The perimeter of a rectangle is 140 cm. If the breadth of the rectangle is 0.4 m, find its length. Also find the area of the rectangle.

Answer 1

Answer:

p= 2l+ 2b, so, 140= 2l + 2b, 140= 2l+.8, 2l= 140- 0.8, 2l= 13.2, so, l= 13.2/2 =6.6

Answer 2

RECTANGLE

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Solve for Length:

$\large \implies \sf \Large{P=2l+2w}$

$\large \tt \red{given} \begin{cases} \sf \:P=140cm \\ \sf \: w = 0.4m \end{cases}$

$\:$

Convert to centimeters:

$\sf \large1\: m = 100 \: cm \\ \sf \large1 \times 0.4 \: m = 100 \times 0.4 \: cm \\ \sf \large0.4 \: m = 40 \: cm \: \: \: \: \:$

$\:$

$\large \implies \sf \Large{140=2l+2(40)}$

$\large \implies \sf \Large{140=2l+80}$

$\large \implies \sf \Large140 - 80 = 2l$

$\large \implies \sf \Large60 = 2l$

$\large \implies \sf \Large \frac{60}{2} = \frac{ \cancel2l}{ \cancel2}$

$\large \implies \sf \Large \therefore \: 30 = l$

$\:$

Final Answer:

$\sf \huge \orange{30cm \: is \: the \: length}$

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Solve for Area:

$\large \implies \sf \Large A=l \times w$

$\large \tt \red{given} \begin{cases} \sf \:l=30cm \\ \sf \: w = 40cm \end{cases}$

$\large \implies \sf \Large A=30cm \times 40cm$

$\large \implies \sf \Large \therefore \: A=1200 {cm}^{2}$

$\:$

Final Answer:

$\sf \huge \orange{1200 {cm}^{2} \: is \: the \: area}$

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