Question

The perimeter of a rectangle is 150cm.the length is 15cm greater than the width.find the dimensions.is 15cm. Greater than the width.find the dimensions.

Answer 1

$let \: b = x \\ so \: l = x + 15 \\ atq \\150 = 2(x + x + 15) \\ 150 \div 2 = 2x + 15 \\ 75- 15 = 2x \\ 60 \div 2 = x \\ x = 30 \\15 + x = 30 + 15 = 45$

Answer 2

Let the length be x

Also let the breadth be x

Given:

Perimeter =150cm

Length=15cm more than breadth

To find:

Length and breadth

Solution:

length=x+15

breadth =x

So,

(x+15)+x+(x+15)+x=150cm

4x+30=150cm

4x=150-30

4x=120cm

x=120/4

=30

x=30

x+15=45

x=30

x+15=45

The four dimensions are 30, 45, 30, 45