Question

The perimeter of a rectangle is 158 cm. If the breadth of the rectangle is 28 cm, find its length. also find the area of the rectangle.

and

Find the value of x : 8x+4=3(x-1)+7


do these questions with the explanation pls i need it fast

Answer 1

Answer:

1. Perimeter = 158 cm

Breadth = 28 cm

Length = x

Perimeter of a rectangle = 2(x + b)

158 cm = 2(x + b)

158 cm = 2(x + 28)

158 = 2x+ 56

158 - 56 = 2x

102 = 2x

102/2 = x

51 = x

Length = 51 cm

Area = l * b

Area = 51 * 28

Area = 1,428 cm²

2. 8x + 4 = 3(x - 1) + 7

8x + 4 = 3x - 3 + 7

8x + 4 = 3x + 4

8x - 3x = 4 - 4

5x = 0

x = 0/5

x = 0

Answer 2

Question 1:

The perimeter of a rectangle is 158 cm. If the breadth of the rectangle is 28 cm, find its length. also find the area of the rectangle.

Answer:

Given,

The perimeter of a rectangle= 158 cm

Breadth = 28 cm

We know that the perimeter of a rectangle = 2 ( l+ b)

[Opening the brackets] → 2l +2b = 158 cm

= 2l + 2 x 28 = 158 cm

2l + 56 = 158 cm

2l = 158 - 56 = 102

Therefore length = 102/2 = 51 cm

Formula for area of a rectangle = l x b

= 51 x 28 = $1428cm^2$

Therefore,

Length of the rectangle = 51 cm

Area of the rectangle = $1428cm^2$

Question 2:

Find the value of x : 8x+4=3(x-1)+7

Answer:

8x+4 = 3(x-1)+7

[opening the brackets]

= 8x+4 = 3x-3+7

[moving the variables to one side and the constants to the other side]

= 8x - 3x = -3 +7 -4

[ The LHS becomes 0 as we can cut off the negatives as well as the positives by cutting off -7 and 7]

= 5x = 0

Therefore the value of x = 0