The perimeter of a rectangle is 24 centimetres and its area is 32 square centimetres . a) What is the sum of the lengths of the longer and the shorter sides of the rectangle ? b)Write down a second degree equation by taking the length of the longer side as 6 + x c) What are the lengths of its the sides ?
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Answer:
a) 12
b) 4x+12=24
Step-by-step explanation:
c) x+y =12 as 2*(x+y)= perimeter
nd x*y =32 which is area
so we get x= 12-y (from above)
so, (12-y)*y = 32
-y² +12y = 32
0= y²-12y +32
0= y² -8y-4y +32
so y = 8 nd y =4
(...I think there is some error..)
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