The perimeter of a rectangle is 240 cm. If its length is increased by 10% and its breadth is decreased by 20%, we get the same perimeter. Find the length and breadth of the rectangle.
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Answer:
So,
Step-by-step explanation:
Perimeter of right angle given = 240 cm
let
- the length of the rectangle Y CM be the breadth of the rectangle
A/Q
2(x+y)=240
⇒x+y=120 [First equation]
Now, its length is increased by 10% and its breadth is decreased by 20%
So, the new length be= 10/100x
= 100x+10x/100
=110x/100
=11x/10
- And the new breadth be = y− 20/100y
= 100y-20y/100
=80y/100
=8y/10
- With new length and breadth we get same perimeter.
So,
⇒2(11/10*+8/10y) =240
⇒11/10*8/10y =120
⇒11x+8y=1200 [Second equation]
- Now, Second equation −8× [First equation], we get
3x=240
⇒x=80
- Putting this value isn First equation,
- y=120−80=40
So, length =x =80cm
& breadth = y= 40 cm
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