The perimeter of a rectangle is 240 cm. If its length is decreased by 10% and its breadth is increased by 20%, we get the same perimeter. Find the dimensions of the rectangle.
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240=2(l-10+b+20)
let l=110
let b=-32
l-10=110-10=100
b+20=-32+20=12
2(l+b)=240
2(100+12)=240
let l=110
let b=-32
l-10=110-10=100
b+20=-32+20=12
2(l+b)=240
2(100+12)=240
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