Question

the perimeter of a rectangle is 26 cm what are the dimensions if the length is 3cm more than that of the width ​

Answer 1

Answer :

Length = 8 cm

Breadth = 5 cm

Solution :

Let L and B be the length and breadth of the rectangle .

According to the question ,

Length is 3 cm more than its breadth .

Thus ,

L = B + 3

Also ,

It is given that , the perimeter of the rectangle is 26 cm .

Thus ,

=> P = 26

=> 2(L + B) = 26

=> 2(B+3 + B) = 26

=> 2(2B + 3) = 26

=> 2B + 3 = 26/2

=> 2B + 3 = 13

=> 2B = 13 - 3

=> 2B = 10

=> B = 10/2

=> B = 5

Also ,

=> L = B + 3

=> L = 5 + 3

=> L = 8

Hence ,

Length = 8 cm

Breadth = 5 cm

Answer 2

Answer:

$\huge \bf \: given$

• Perimeter of rectangle = 26 cm
• Length is 3 cm more than breadth

$\huge \bf \: to \: find$

Length and breadth

$\huge \bf \: solution$

Let

Breadth of rectangle = x

Length of rectangle = x + 3

Now,

As it is given perimeter is 26 cm.

Therefore,

$\sf \implies \: 26 = 2(x + 3 + x)$

Now,

$\sf \implies \: 26 = 2(x + 3 + x)$

$\sf \implies 26 = 2 \times (2x + 3)$

$\sf \implies \: 2x + 3 = \dfrac{26}{2}$

$\sf \implies \: 2x + 3 = 13$

$\sf \implies \: 2x = 13 - 3$

$\sf \implies \: 2x = 10$

$\sf \implies \: x = \dfrac{10}{2}$

$\sf \implies \: x \: = 5$

Therefore,

Breadth = 5 cm

Length = 5 + 3 = 8 cm

Let's verify

It is given the length is 3 cm more than breadth and perimeter is 26 cm.

$\sf \: 26 = 2(x + 3 + x)$

$\sf 26 = 2(5 + 3 + 5)$

$\sf \: 26 = 2 \times 13$

$\sf \: 26 = 26$

Hence verified.