Question

The perimeter of a rectangle is 30 meters . If its length exceeds its breadth by 3 meter , then find its length ?

Answer 1

Answer:

9m

Step-by-step explanation:

given that the length is 3m more than the breadth.

let the breadth be x, therefore length will be 3+x.

perimeter of the rectangle = 30m

= 2(l+b) = 30m

= 2(3+x+x) = 30m

= 2(2x+3) = 30m

= 2x+3 = 30/2

= 2x+3 = 15

= 2x = 15-3

= 2x = 12

= x = 12/2

= x = 6m

hence, breadth of the rectangle = x

= 6m

length of the rectangle = x+3

= 6+3

= 9m

Answer 2

Length of rectangle = 9 meters  

Given:

The perimeter of a rectangle = 30 meters

The length exceeds its breadth by 3 meter  

To find:

Length of the rectangle

Solution:

Let x be the breadth

Given that the length exceeds its breadth by 3 meter

⇒ Length = x+3  

As we know perimeter of a rectangle = 2(length+breadth)

⇒ 2(x+3 + x) = 2(2x+3)

From given data perimeter = 30 meters

⇒ 2(2x+3) = 30

⇒ 2x + 3 = 15

⇒ 2x = 12

⇒ x = 6 meters

Therefore, length  (x+3) = 6 + 3 = 9 meters

Length of rectangle = 9 meters

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