Question

The perimeter of a rectangle is 32 m. Its length is 10 m, find its breadth 

Please answer fast​

Answer 1

Answer:

breadth is 6m

Step-by-step explanation:

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Answer 2

Question:

The perimeter of a rectangle is 32 m. Its length is 10 m, find its breadth.

To find:

• Breadth of rectangle

Given:

• Perimeter of rectangle = 32 m

• Length of rectangle = 10 m

Let:

• Breadth of rectangle = x

Solution:

We know :

$\bigstar \boxed{ \rm perimeter \: of \: rectangle = 2(length + breadth}$

By using this formula we can find value of breadth of rectangule

$: \implies\sf perimeter \: of \: rectangle = 2(length + breadth$

Insert Value of length,breadth (which we have supposed) and Perimeter of rectangle.

$: \implies\sf 32= 2(10 + x)$

$: \implies\sf \dfrac{32}{2} = (10 + x)$

$: \implies\sf \cancel\dfrac{32}{2} = (10 + x)$

$: \implies\sf (10 + x) = 16$

$: \implies\sf x= 16 - 10$

$: \implies \underline{ \boxed{\sf x= 6m}}$

As we have supposed Breadth as x

.°. Breadth of rectangle = 6m

Now Let's Verify whether value of Breadth is correct or not

$: \implies\sf 32= 2(10 + x)$

Put value of x in this equation:

$: \implies\sf 32= 2(10 + 6)$

$: \implies\sf 32= 2(16)$

$: \implies\sf 32= 2 \times 16$

$: \implies \underline{ \boxed{\sf 32= 32}}$

$\large \gray\dag \blue{ \underline{ \sf RHS=LHS }}\gray\dag$

Hence Verified!

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