the perimeter of a rectangle is 3ab + 2bc- 4ca. and the length is ab-bc-ca. find the breadth of the rectangle
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Answered by
1
Answer:
(1/2)ab+2bc-ca
Step-by-step explanation:
1/2[(3ab+2bc-4ca)-2(ab-bc-ca)]
=1/2[3ab-2ab+2bc+2bc-4ca+2ca]
=1/2[ab+4bc-2ca]
=(1/2)ab+2bc-ca
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Answered by
0
Answer:
Step-by-step explanation:
perimeter of a rectangle is 2×(l+b)
length=ab-bc-ca
∴ 3ab + 2bc- 4ca= 2×(ab-bc-ca)
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