The perimeter of a rectangle is 40 cm. Can it's area be 120 square centimetre. Why
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The perimeter of a rectangle is twice its length plus twice its width. So 2L + 2W = 40 The area of a rectangle is its length times its width.
Answered by
1
The perimeter of a rectangle is twice its length plus twice its width. So
2L + 2W = 40
The area of a rectangle is its length times its width. So
LW = 120 or
L = 120/W so
2 (120/W) + 2W = 40 or simplifying by dividing all terms by 2
120/W + W =20
Multiplying all terms by W gives you
120 + W^2 = 20W and by rearranging the terms
w^2 - 20W + 120 = 0 which can be solved using the quadratic formula
one of which parts is the square root of (b^2 - 4ac) which in this equation is
(20^2 - 4*120)^.5 or
(400 - 480) ^.5 or
(-80)^.5 which is an imaginary number and so
In real numbers, its area cannot be 120 sq cm.
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