Question

The perimeter of a rectangle is 40 cm. The length of the rectangle is
more than double its breadth by 2. Find length and breadth.
solve by eliminating method.​

Answer 1

Answer:

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Perimeter of rectangle =40 cm (given)

condition :- length = 2× breadth +2

⇒l=2b+2

perimeter p=2(l+b)=40

⇒2(2b+2+b)=40

⇒2(3b+2)=40

⇒6b=40−4=36

∴b=6cm

l=2×6+2=12+2=14cm

∴ length =14 cm, breadth =6 cm

Step-by-step explanation:

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