the perimeter of a rectangle is 40cm the length of the rectangle is less than double its breadth by 1cm find the length and breadthl
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Answered by
8
Answer:-
Let the breadth of the rectangle be x cm.
Given:
Length is 1 cm less than twice the breadth.
So, Length = (2x - 1) cm.
And,
Perimeter of the rectangle = 40 cm.
We know that,
Perimeter of a rectangle = 2(length + breadth)
So,
⟹ 40 = 2(2x - 1 + x)
⟹ 40 = 2(3x - 1)
⟹ 40 = 6x - 2
⟹ 40 + 2 = 6x
⟹ 42/6 = x
⟹ 7 cm = x
∴
Length of the rectangle = 2x - 1 = 2(7) - 1 = 14 - 1 = 13 cm.
Breadth of the rectangle = x = 7 cm
Answered by
0
Answer:
Perimeter of rectangle =40 cm (given)
condition :- length = 2× breadth +2
⇒l=2b+2
perimeter p=2(l+b)=40
⇒2(2b+2+b)=40
⇒2(3b+2)=40
⇒6b=40−4=36
∴b=6cm
l=2×6+2=12+2=14cm
∴ length =14 cm, breadth =6 cm
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