the perimeter of a rectangle is 40m If the sides of the rectangle are natural number find the dimensions of the rectangle having the maximum area
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Answered by
13
Answer:
Step-by-step explanation:
Answered by
25
Step-by-step explanation:
let side be x and y
perimeter is 40m
so
2(x+y)=40
x+y=40/2
x+y=20
then find two numbers whose sum is 20 and largest product
we find 10,10 number
whose sum 20 and largest product
so
area of rectangle is 10*10
100
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hope it helps you
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