Question

two concentric circle circle one and Circle to are in radii of 5 cm and 3 cm find the length of the chord of circle one tangent to Circle to at length​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

hello users 

solution

In triangle OAD and OBD

OA = OB = 10 cm (Radius of larger circle)

And

OD = 6 cm ( Radius of smaller circle)

And

AD and BD are the length of tangents

And

AB = length of chord of larger circle 

Here

Using Pythagoras theorem 

H² = B² + P² 

Here

AD = BD =√ (OA² - OD²)  = √ (OB² -  OD² )

=> AD = √ (10² - 6²)  

= √ (100 - 36)

= √ 64 

= 8 cm 

=> AD = BD = 8 cm 

Hence 

the length of chord = AB

= AD + BD 

= 8 cm + 8 cm

= 16 cm Answer

# hope it helps :)

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