Question

The perimeter of a rectangle is 40m .It's length if four times less than five times it's breadth.Find the area of the rectangle.​

Answer 1

Correct answer:-

64m^2.

Explanation:-

Let, breadth of rectangle is x, then 5x−4 be the length of the rectangle.

Perimeter of rectangle =2(l+b)

⇒40=2(l+b)

⇒40=2(5x−4+x)

⇒40=12x−8

⇒12x=40+8

⇒12x=48

⇒x=48/12

⇒x=4

Breadth =4 meters

Hence, length =5×4−4=20−4=16m

Therefore, area of rectangle =(L×b)

=16×4

=64m^2.

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Answer 2

• As per the data given in the question, we have to find the value of the expression.

            Given data:- Perimeter of the rectangle is $40m.$

            To find:-Area of the rectangle.    

             Solution:-

• The angle of the rectangle is 90°.

• The diagonal of a rectangle bisect each other.

• The Sum of all interior angles is equal to360 °.

     Let, breadth of a rectangle is $x$,  then $5x-4$ be the length of the rectangle.  

      Perimeter of rectangle$=2(l+b)$

           $\begin{array}{l}\Rightarrow 40=2(1+b) \\\Rightarrow 40=2(5 x-4+x) \\\Rightarrow 40=12 x-8 \\\Rightarrow 12 x=40+8 \\\Rightarrow 12 x=48 \\\Rightarrow x=\frac{48}{12} \\\Rightarrow x=4\end{array}$

       Breadth$=4$ metes.

    Hence length $=5 \times 4-4=20-4=16 \mathrm{~m}$

Therefore the area of rectangle$}=\mathrm{lb}=16 \times 4=64 \mathrm{~m}^{2}$.