The perimeter of a rectangle is 40m. It's length is 4m less than five times of it's breadth.find the area of the rectangle
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PERIMETER=40m
The length = 5(breadth)-4
PERIMETER=2(l+b)
40 =2(5b-4+b)(Substituting value of length)
40/2 = 6b-4
20=6b-4
20+4 = 6b
24=6b
b=4cm
Length=5b-4=5(4)-4=20-4=16
AREA OF THE RECTANGLE= length*breadth
=16*4
=64cm^2 (sqr is only for unit).
The length = 5(breadth)-4
PERIMETER=2(l+b)
40 =2(5b-4+b)(Substituting value of length)
40/2 = 6b-4
20=6b-4
20+4 = 6b
24=6b
b=4cm
Length=5b-4=5(4)-4=20-4=16
AREA OF THE RECTANGLE= length*breadth
=16*4
=64cm^2 (sqr is only for unit).
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Answer:
Step-by-step explanation:
Given,
Perimeter=40m
Length=(5b-4)
Perimeter=2(l+b)
40=2(5b-4+b)
40=2(6b-4)
20=6b-4
20+4=6b
24=6b
4=b;sub the b=4 in length
length=5(4)-4
=20-4=16m square
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