Question

the perimeter of a rectangle is 44cm. its length exceeds twice its breadth by 4 cm . find the length and breadth of the rectangle

Answer 1

Hi friend!!

Let l be the length of a rectangle and b be the breadth of the rectangle.

Given, length exceeds twice its breadth by 4 cm

→l=2b+4

Also, perimeter=44cm

2(l+b)=44

2(2b+4+b)=44

3b+4=22

3b=18

b=6cm

l=2b+4=2(6)+4=16cm

I hope this will help u;)

Answer 2

Concept

A two-dimensional shape's perimeter is the overall length of the outline. We sum the lengths of all four sides to determine the perimeter of a rectangle.

Given

Perimeter of rectangle = 44cm

Length exceeds twice its breadth by 4cm

Find

We need to find the length and breadth f the perimeter

Solution

Let the breadth be x

So , according the statement the length will be 2x+4

Now , We know that perimeter of the rectangle =  2 (length + breadth)

∴ Perimeter = 2(2x+4+x)

44 = 4x+8+x

44 = 6x+8

∴ 36 = 6x

∴ x  = 6

So the breadth here is 6 cm

Now Calculate the length

Length = 2(6)+4 = 16

Hence the length is 16cm

Final Answer

Length is 16 cm and Breadth is 6cm

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