the perimeter of a rectangle is 46 cm and its length is 15 M find its (1) breadth (2)area (3) diagonal
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Answered by
30
@
1)P=2(l+b)
46cm=2(15+b)
46cm=30+2b
(46-30)cm=2b
16cm=2b
8cm=breadth
_____________
2)Area =l×b
15×8
120cm=Area of rectangle
_____________
3)Diagonal
H²=P²+b²
H²=(15)²+(8)²
H²=289
H=17cm
Diagonal =17cm
@:-)
1)P=2(l+b)
46cm=2(15+b)
46cm=30+2b
(46-30)cm=2b
16cm=2b
8cm=breadth
_____________
2)Area =l×b
15×8
120cm=Area of rectangle
_____________
3)Diagonal
H²=P²+b²
H²=(15)²+(8)²
H²=289
H=17cm
Diagonal =17cm
@:-)
Answered by
25
Perimeter = 46 cm
Length =15 cm
Let us assume lenght as 'l' and breadth as 'b'
(1) BREADTH
Perimeter= 2(l+b)
46= 2(15+b)
46=30 + 2b
2b= 46-30
2b= 16
b= 8cm
Ans- Therefore, breadth is 8cm.
Area = l×b
=15×8
=120cm²
Ans- Therefore, area is 120cm²
Diagonal= √l²+b²
=√15²+8²
=√225+64
=√289
=17cm
Ans- Therefore, diagonal is of 17cm.
Length =15 cm
Let us assume lenght as 'l' and breadth as 'b'
(1) BREADTH
Perimeter= 2(l+b)
46= 2(15+b)
46=30 + 2b
2b= 46-30
2b= 16
b= 8cm
Ans- Therefore, breadth is 8cm.
Area = l×b
=15×8
=120cm²
Ans- Therefore, area is 120cm²
Diagonal= √l²+b²
=√15²+8²
=√225+64
=√289
=17cm
Ans- Therefore, diagonal is of 17cm.
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