the perimeter of a rectangle is 50 cm if its length exceeds its breadth by 5 centimetre find the dimension of the rectangle
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perimeter=2( l+b )
50=2(l+l-5)because breadth is 5 less than lenth
50/2=l+l-5
25=2l-5
25+5=2l
30=2l
15=l
therefore breadth = 15-5=10
50=2(l+l-5)because breadth is 5 less than lenth
50/2=l+l-5
25=2l-5
25+5=2l
30=2l
15=l
therefore breadth = 15-5=10
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