The perimeter of a rectangle is 52 cm. How long is each size if the width is 2 cm more than one-third of the length?
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Answer:
perimeter is 52 and 2(l+b)
let l=x
b=x/3 +2
2(x+x/3+2)
2(3x+x+6/3)
8x+12/3=52
8x+12=52×3
8x=156-12
8x=144
x=18
length is 18
breadth is 10
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