the perimeter of a rectangle is 72 M its breadth is 10 M less than the length find the dimensions of the rectangle
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let be the length of rectangle = x
Perimeter of rectangle = 2(l+b)
72 m = 2(l+b)
l+b = 72/2
l+b = 36 m
According to question , x+x-10 = 36m
2x = 36 + 10
2x = 46
x = 23m
length = 23 m
Breadth = 23-10
= 13m
Perimeter of rectangle = 2(l+b)
72 m = 2(l+b)
l+b = 72/2
l+b = 36 m
According to question , x+x-10 = 36m
2x = 36 + 10
2x = 46
x = 23m
length = 23 m
Breadth = 23-10
= 13m
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