Question

the perimeter of a rectangle is a 120 CM the ratio of its Length and width is a 2:1 find the area of a rectangle​

Answer 1

Let the length be l and breadth be b

then

2 (l+b)= 120

l+b= 60 cm

Also

l/b = 2/1

l = 2b

Putting l= 2b

2b + b = 60

b = 20

l = 40

Area = lb = 40 ×20

=800cm^2

Answer 2

Answer:

length = 40 cm

breadth = 20 cm

Step-by-step explanation:

given that,

the perimeter of a rectangle is a 120 cm

also,

given the ratio of its sides = 2:1

let the common ratio of their sides be x

so,

length of the rectangule = 2x

hence

breadth = x

and

we know that

perumeter of a rectangle

= 2(length + breadth)

here.

length = 2x

breadth = x

given perimeter = 120 cm

putting the values,

2(2x + x) = 120

2x + x = 120/2

3x = 60

x = 60/3

x = 20

so,

breadth of the rectangle = x

= 20 cm

length of the rectangle = 2x

= 2(20) = 40 cm

so,

length = 40 cm

breadth = 20 cm