find the 31 st term of an AP whose 11th term is 38 and 6th tern is 73.
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a+10d=38----------1
a+5d=73----------2
Solve the equations.
a+10d=38
a+5d=73
➡5d= -35
➡d= -7
From eq 1.
a+10d=38
a+10×(-7)=38
a-70=38
a=108
Now 31 term=a+30d
=108+30×(-7)
=108-210
= -102.
Hope it helps.....
alirasim551:
thanks
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