Question

the perimeter of a rectangle is a 52 M if it width is a 2 m more than one third of its length of find the dimension of a rectangle

Answer 1

perimeter =52m
let,length=x
width=1/3x+2
so,
perimeter =2 (l+b)
52=2(x+1/3x+2)
52=2 (4x/3+2)
52/2=4x/3+2
26×3/4=x+2
78/4=x+2
78/4-2=x

so,
length=x=18
breadth =1/3x+2=6+2=8