Question

The perimeter of a rectangle is equal to that of a square with side 13 m. If the rectangle is 16 m long, what is its breadth​

Answer 1

Step-by-step explanation:

Here is your answer.

I have written in short form.

perimeter of rectangle= 2(l+b)

perimeter of square= 4 × sides

Answer 2

Question

The perimeter of a rectangle is equal to that of a square with side 13 m. If the rectangle is 16 m long, what is its breadth.

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

Required Answer​

• 10 meters

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

Given

• Perimeter of square is equal to perimeter of rectangle

• Side of square=13 meters

• length of rectangle=16m

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

To Find

• Breadth=?

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

Formula Using

${\large{\underline{\pmb{\frak{Perimeter\:of\:Square}}}}}$

$\bigstar{\underline{\boxed{\sf{Perimeter_{\:square}=\red{4s}}}}}$

${\large{\underline{\pmb{\frak{Perimeter\:of\:Rectangle}}}}}$

$\bigstar{\underline{\boxed{\sf{Perimeter_{\:rectangle}=\red {2(l+b)}}}}}$

Here

• s=side
• l=length
• b=breadth

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

${\quad{\Large{\underline{\underline{\blue{\bf{Solution}}}}}}}$

$\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

${\large{\underline{\pmb{\frak{Calculating\:Perimeter}}}}}$

${\qquad{\qquad\:\:\:{\longmapsto{\sf{Perimeter_{\:square}=4s}}}}}$

${\qquad{\qquad\:{\longmapsto{\sf{Perimeter=4 \times 13}}}}}$

${\qquad{\qquad\:{\longmapsto{\sf{Perimeter=\green{52\:meters}}}}}}$

• Perimeter of square=Perimeter of rectangle

• ${\therefore}$Perimeter of rectangle=52 metres.

$\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

${\large{\underline{\pmb{\frak{Calculating\:Breadth}}}}}$

${\qquad{\qquad{\longmapsto{\sf{Perimeter_{\:rectangle}=2(l+b)}}}}}$

${\qquad{\qquad{\longmapsto{\sf{52=2(16+b)}}}}}$

${\qquad{\quad{\longmapsto{\sf{\dfrac{52}{2}=16+b}}}}}$

${\qquad{\quad\:{\longmapsto{\sf{26=16+b}}}}}$

${\qquad{\quad{\longmapsto{\sf{b=26-16}}}}}$

${\qquad{\quad{\longmapsto{\sf{breadth=\green{10\:meters}}}}}}$

$\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

$\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}} \end{gathered}$

~Therefore

• Breadth of given rectangle is 10 metres

$\begin{gathered} \\ {\underline{\rule{200pt}{7pt}}} \end{gathered}$