Question

Triangle ABC is right angled at B with sides making right angle as 10 cm and 24 cm. Find the radius of the circle inscribed in this triangle. I will make atleast 100 accounts.
Shruti 2 warnings are nothing for me ​

Answer 1

refer the attachment hope its help u

same here

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Answer 2

Answer:

triangle ABC is right angle where angle A= 90and AB = 6 cm and AC = 8cm

O be the center of circle and r is AB, BC,CA are tangents to circl

Area of triangle ABC= 1 /2 × AB ×h

= 1/2 ×6×8=

${24}cm^{2}$

By pythagoreas theorm

${bc}^{2} = {ac}^{2} + {ab}^{2}$

$= {8}^{2} + {6}^{2} = 64 + 36 \\ = 100$

$bc = \sqrt{100} = 10$

Area ∆ ABC=Ar ∆ OAB+Ar ∆ OBC+ tr ∆ OAB+Ar∆ obc +Ar triangle OCA

$24 = 1/2 \times r \times A \times B + 1/2 \times r \times B \times C + 1/2 \times r \times C \times A$

$24 = 1/2 \times r \times (AB + BC + CA)$

$48 = r(6 + 8 + 10)$

$= r = \frac{48}{24} = 2cm$

LOL I wasted time writing wrong answer...

but now I think you got more warnings (‘◉⌓◉’)

I HOPE THIS WRONG ANSWER

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