The perimeter of a rectangle is
numerically equal to the area of a
Square. If the perimeter of given
square is om and the ratio of length
to breadth of the rectangle is 3:2.
Find dimension of the rectangle.
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Answer:
For example
perimeter of rectangle = area of rectangle
2(l+b)=lb.
if b=2×43=411cm
l=?
2(l+411)=l(411)
2l−(411l)=−211
⇒43l=211⇒l=322=731cm
∴ if breadth =243cm than length = 731cm
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