Question

the perimeter of a rectangle of length 17cm is 64cm. find its area

Answer 1

Area is 255
because
perimeter=2(l+b)
64=2(17+b)
64÷2=17+b
32=17+b
32-17=b
so, breadth=15
therefore,Area=l×b
area=17×15
area=255

Answer 2

The area of the rectangle is 255 cm².

Given:

• The perimeter of the rectangle is 64 cm.
• The length of the rectangle is 17 cm.

To find:

• Find the area of rectangle.

Solution:

Concept formula to be used: If 'l' is length and 'b' is the breadth of a rectangle.

• Perimeter of rectangle:$\bf 2(l + b)$

• Area of rectangle:$\bf l \times b$

Step 1:

Find the width of the rectangle.

Put the values in the formula of perimeter.

$64 = 2(17 + b)$

$17 + b = \frac{64}{2}$

$17 + b = 32$

$b = 32 - 17$

$\bf b = 15$

Thus,

The breadth of the rectangle is 15 cm.

Step 2:

Find the area of the rectangle.

Put the values of length and breadth in the formula.

$Area = 17 \times 15$

$\bf Area = 255 \: {cm}^{2}$

Thus,

Area of rectangle is 255 cm².

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