Question

the perimeter of a rectangle plot of land us 114 metres and its ares is 810 square metres.1)take the length of plot as x metres.use the perimeter 114 m to write the value os the breadth in terms of x.2)usethe values of length ,breadth and area to write an equationin x.3)solve the equation to find the length and breadth of the plot​

Answer 1

GIVEN :-

• Perimeter of the rectangle plot = 114 m
• Area of the rectangle plot = 810 m²

SOLUTION :-

1. Perimeter = 2(Length + Breadth)

                   $\longrightarrow \sf 2(x+b)=114\\\\\longrightarrow x+b = 57\\\\\longrightarrow\bf b = 57-x$

     2.  Area = Length × Breadth

               

                   $\longrightarrow \sf x(57-x) = 810\\\\\longrightarrow 57x-x^2 = 810\\\\\longrightarrow x^2-57x =-810\\\\\longrightarrow \bf x^2-57x+810 = 0$

     3.  Equation → $\sf x^2-57x+810 = 0$

                   

                      $\longrightarrow \sf x^2-57x+810=0\\\\\longrightarrow x^2-30x-27x+810=0\\\\\longrightarrow x(x-30) - \ 27(x-30) = 0\\\\\longrightarrow (x-30) \ (x-27) = 0 \\\\\longrightarrow \bf x =30 \ , \ x=27$

• If length = 30m , breadth = 57 - 30 = 27m

• If length = 27m , breadth = 57 - 27 = 30m

Answer 2

Answer:

length=30m

breadth=27m

Step-by-step explanation:

Plz see the photo...