The perimeter of a rectangle whose length is twice its breadth and breadth 2 units is
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Perimeter of a rectangle is 2(l+b)
L=2b
B= b
Perimeter =2*(2b+b)
=2*3b
=5b
Here b = 2
Therefore 5*2= 10 m
L=2b
B= b
Perimeter =2*(2b+b)
=2*3b
=5b
Here b = 2
Therefore 5*2= 10 m
Answered by
4
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