the perimeter of a rectangular field is 54meter and its area is 180m^2 find the length and breadth of the rectangle
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let the sides of rectangle are a & b
2(a+b ) = 54
a×b = 180
a+b = 27
now (a-b)^2 = (a+b)^2 -4ab
(a-b)^2 = 27^2 -4×180
(a-b)^2 = 729 - 720
(a-b)^2 = 9
a- b = 3
a + b = 27
2a = 30 , = a = 15
b = 12
Length = 15m
Breadth = 12m
2(a+b ) = 54
a×b = 180
a+b = 27
now (a-b)^2 = (a+b)^2 -4ab
(a-b)^2 = 27^2 -4×180
(a-b)^2 = 729 - 720
(a-b)^2 = 9
a- b = 3
a + b = 27
2a = 30 , = a = 15
b = 12
Length = 15m
Breadth = 12m
Answered by
0
perimeter = 2(l+b) =54
area = l*b=180
solve 2 equations
area = l*b=180
solve 2 equations
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