Question

the perimeter of a rectangular field is 70 metre and its length is 15m longer than its breadth ​

Answer 1

$\huge\underline\frak\purple{Solution}$

Perimeter of rectangle = 70

Let breadth be x

then length be 15+x

according to question

2(l+b) = 70

2(15+x+x) = 70

2(15+2x) = 70

30+4x = 70

4x = 70 - 30

x = 40/4 = 10m

So ,

breadth = 10m

length = 15+x = 15+10 = 25

$\large\underline\bold\red{NOTE :-}$

Perimeter of rectangle = 2(l+b)

Answer 2

▂ ▄ ▅ ▆ ▇ █ SOLUTION █ ▇ ▆ ▅ ▄ ▂

☆GIVEN☆

• The perimeter of rectangle=70m

☆LET

• The breadth of rectangle be X
• The length of rectangle be X+15

☆According to the above information☆

☆Perimeter of rectangle=2(L+B)☆

$⇒70 = 2(x + 15 + x) \\ \\ ⇒70 = 2(2x + 15) \\ \\ ⇒35 = 2x + 15 \\ \\ ⇒2x = 35 - 15 \\ \\ ⇒2x = 20 \\ \\ ⇒x = 10$

✮HENCE:-

• THE BREADTH=10m
• THE LENGTH=25m

✮FOR VERIFICATION✮

➞Perimeter=2(l+b)

➞70=2(25+10)

➞70=70

HENCE, PROVED