The perimeter of a rectangular paper of breadth 23/2cm is 30 cm Find the length of the paper
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\bf{ \underline{ \underline{answer \: : }}} \\ \\
⟹\mathrm{Perimeter} = 2(l + b) \\ \\⟹\mathrm{Perimeter} = 2l + 2b \\ \\ ⟹\mathrm{Perimeter} \: = 2l + 2 \times \frac{23}{22} \\ \\ ⟹30 \: cm = 2l + 2 \: cm \\ \\ ⟹ 30 \: cm - 2 \: cm = 2l \\ \\ ⟹28 \: cm = 2l \\ \\ ⟹ \frac{28 \: cm}{2} = l \\ \\ ⟹l = 14 \: cm
\large\bold\red{answer~is \: 14 \: cm \: .} \\ \\ \mathrm{ mark \: as \: brainliest \: answer \: and} \\ \mathrm{plz \: follow \: me. \: }
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