the perimeter of a rectangular plate is 26cm,where length is 5cm more than the width of the plate.Find the pair of linear equations for the above situation and hence find the dimensions of the plate by the graphical solution of the linear equations
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Perimeter of rectangle is 52cm
Length is 6cm
Breadth =?
Let breadth be x
Perimeter of rectangle = 2 (l+b)
52 = 2 (6+x)
52=12 + 2x
52 - 12=2x
40 = 2x
40÷2 = x
20= x
therefore width of rectangle is 20cm
The dimensions of rectangle are
6cm , 20cm, 6cm, 20cm
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