Question

the perimeter of a rectangular plot is 174 metre and its breadth is 35 metre find the length and the area of the plot​

Answer 1

Answer:

Perimeter = 2 ( L + B )

174 = 2 ( L+ 35 )

174 = 2L + 70

174-70 = 2L

104/2 = L

52m = L

Area = L x B

= 54 x 35

= 1890m²

Answer 2

Required Solution :

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• $\textsf{⟼ Length (l) of the rectangular Field = 52m.}$

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• $\textsf{⟼ Area of the rectangular Field = 1820 m².}$

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✡ GIVEN :-

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• $\textsf{⟼ Perimeter of a rectangular plot = 174m.}$

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• $\textsf{⟼ Breath of the rectangular plot = 35m.}$

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✡ TO FIND :-

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• $\textsf{⟼ 1) Length of the rectangular plot}$

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• $\textsf{⟼2) The area of the rectangular plot}$

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Solution :

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⟼ (1) Length

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• $\textsf{Perimeter of a rectangle = 2 (l+b)}$

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Here,

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• $\textsf{ ⟼ Breadth(b) of the rectangular Field = 35m.}$

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• $\textsf{⟼ Perimeter of the Rectangular Field = 174 m.}$

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• $\textsf{ ⟼ 174 = 2 ( l+35 )}$

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• $\textsf{ ⟼ 174 = 2l + 70}$

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• $\textsf{ ⟼ 174 - 70 = 2}$

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• $\textsf{ ⟼104 = 2}$

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• ⟼ $\sf l =\dfrac{104}{2}$

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$\mathfrak{ ☯\; Length \;(l) \;of\; the\; rectangular\; Field \;=\; 52\;m. ☯}$

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The Rectangle Diagram :

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$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 52m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 35m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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(2) AREA

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• $\textsf{ ⟼ Area of a Rectangle = Length(l) × Breadth(b)}$

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Here,

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• $\textsf{⟼ Breadth(b) of the rectangular Field = 35m.}$

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• $\textsf{ ⟼ Length(l) of the rectangular Field = 52m.}$

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• $\textsf{⟼ Area of the rectangular Field = 35 × 52}$

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$\mathfrak{߷\; Final\;Answer :}$

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• $\mathfrak{ ⟼ \; ⚛ \;Area\; of\; the \;rectangular\; Field \;=\; 1820\; m² \;⚛.}$

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$\mathfrak{߷\;Note\; :}$

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• $\textsf{ ⟼\;For\; understanding\; diagram\; clearly \;view \;this\;answer\; in\; brainly.in\;!}$

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