Question

. The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than
twice its breadth. What are the length and the breadth of the pool?

​

Answer 1

hope it helps you..have a nice day!

Answer 2

Question:

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

To find:

• length

• breadth

Given:

• perimeter = 154 m

• Length is 2 m more than twice of it's breadth

Let:

• Breadth = x

• Length = 2 + 2x

Solution:

We know:

$\bigstar \boxed{ \rm{}Perimeter \: of \: rectangle = 2(length \: + \: breadth)}$

By using this formula we can find value of x

$\dashrightarrow\sf{}Perimeter \: of \: rectangle = 2(length \: + \: breadth)$

$\dashrightarrow\sf{}154 = 2(2x + 2 + x)$

$\dashrightarrow\sf{}154 = 2(2x + 2) + 2(x)$

$\dashrightarrow\sf{}154 = (2x \times 2 + 2 \times 2)+ 2(x)$

$\dashrightarrow\sf{}154 = (4x+ 4)+ 2(x)$

$\dashrightarrow\sf{}154 = 4x + 4 + 2x$

$\dashrightarrow\sf{}154 = 6x + 4$

$\dashrightarrow\sf{}154 - 4 = 6x$

$\dashrightarrow\sf{}150= 6x$

$\dashrightarrow\sf{} \frac{150}{6} =x$

$\dashrightarrow\sf{} x = \frac{150}{6}$

$\dashrightarrow\sf{} x =\cancel \frac{150}{6}$

$\dashrightarrow \boxed{\sf{} x =25} \checkmark$

Verification:

$\dashrightarrow\sf{}154 = 2(2x + 2 + x)$

put value of x in this equation

$\dashrightarrow\sf{}154 = 2(2 \times 25 + 2 + 25)$

$\dashrightarrow\sf{}154 = 2(50+ 2 + 25)$

$\dashrightarrow\sf{}154 = 2(5 2 + 25)$

$\dashrightarrow\sf{}154 = 2(77)$

$\dashrightarrow\boxed {\sf{}154 = 154}\checkmark$

LHS = RHS

Hence verified!

Now Let's find dimensions:

• Breadth =x
• Breadth = 25m

• Length = 2 + 2x
• Length = 2 + 2 × 25
• Length = 2 + 50
• Length = 52m