Question

the perimeter of a rhombus is 104 cm. If one diagonal measures 20 cm, find the other diagonal. And mow kf gbe area of the rhombus is equal to yhe area of the rectangle. If breadth= 16cm , find the length of the triangle​

Answer 1

Answer:

smaller diagonal is 20

perimeter of a rhombus is 104

then side of the Rhombus = 104/4 = 26

now divide Rhombus is 4 small right angle triangle

in which you have 26 as hypotenuse and 10 as base in those triangles whose sides are in smaller diagonal side ( in Rhombus if both diagonals intersecting each other each diagonal splits in 2 equal parts )

then using Pythagoras theorem find perpendicular of the triangle

we get 24 which is also the half of the bigger diagonal

so bigger diagonal is 24*2= 48

then area of the Rhombus = 1/2 [ product of both diagonals ]

we get 480 sq unit ANSWER

Step-by-step explanation:

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